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JEEVA

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About JEEVA

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    jeevabala666@gmail.com

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  1. @Rahul R: is it the same for the optistrut solver also....should i not define material or properties for the Rigids while solving in optistrut also......or should i create a seperate prop for rigids as 1D element prop and assign materials?......
  2. JEEVA

    2 d meshing

    viketh if u can say the problem still more clearly then i can see weather i have faced such and see weather i can help u out.......
  3. @Prakash Pagadala: thanks for ur suggestion........i tried repairing the element but nothing was fruitful and finally deleted the mesh and remeshed it again and now the 3D elements are formed properly.....thanks guys @prakash pagadala and @Q.Nguyen-Dai for ur reply.... Then the tet mesh formed has a 2% Tet collapse but jacobian is good......is it ok to neglect and continue with the analysis or should i go for further fine tuning of the mesh......
  4. as u can see the reason that there is no node connectivity so i splitted the element so that it forms a node connectivity to the nearby node.......and now am running tet mesh....wil update the failure/ successful mesh once its finished.......thanks
  5. Nguyen-Dai i have used surface deviation and didnt control the mesh manually....and during 2D mesh i gave min as 0.5 and max as 7 for the element size and growth rate as 1.1......how can i control further more.....should i be reducing the max limit further more.....and how to avoid the negative jacobian....and while going for the tet mesh i found this element being highlighted....does this infer any error.....highlighted error attached.....predicted spot highlighted reason..... Thanks for ur reply....
  6. Guys here i try to mesh a 3D model file and for which i made the 2D mesh on the surface using surface deviation with max min element size and growth rate. then i try to make tetrahedral mesh so i went to 3d-----> tetmesh and selected the 2D elements and gave simple pyramid and meshed it. But while the mesh was on progress error was coming as Input mesh is self intersecting and the mesh formed is only over the surface and it is formed as a seperate CFD trias......... here i have uploaded the snap shot of 2D mesh and corresponding percentage of failure in different 2D mesh checks......from 1 to 8 PICTURE denotes the element check from WARPAGE to JACOBIAN. CFD tria PICTURE shows the mesh formed by wen tat mesh was given. mesh formed over surface alone PICTURE shows the masked view of the inner Cross section self intersecting PICTURE shows the error msg tetmesh PICTURE shows the options selected for tet mesh and its window
  7. and for even constraints is there no card image needed...cause i solved by giving no card image for constraints.....i saw two things which are more likely relevant namely single point constraints SPCCADD AND multipoint constraint MPCCADD but i gave no card image...... and one more thing even wen i go for F1help in hm am not able to find the details of each card image when it should be used.......i use card images only by word of mouth..... can u share me any material on card image i.e some chartsheet form which has the details on which card image should be used for what sort of problems......
  8. thanks rahul i wil follow the alternative3.....but does it add on any additional moments for any irregular lamina.... Eg. if it is a load on a washer then the node is formed in the center so i will define a load in the center node but coming to a irregular laminae the main RBE3 node is formed some where in the space and will it also b a UDL or will it account additional moments...... Thanks in advance What should be the card image used......is it the same LOAD card image or anything else for the UDL
  9. Hi everyone, i have this doubt on how to define a uniform distributed load?..... What all did i try to sort this problem/ alternative solutions tried?....... alternative tried 1 = wen i go for Force tab am able to give force only for points, nodes or components,,,,...so i just divide my load by number of nodes and give it to the individual nodes which is a time consuming process......am not able to give it as a constant force through out the surface in a single go alternative tried 2=else i convert the force to a pressure by manually calculating the area (P=F/A) and i define it to that surface which is still more time consuming process,,..... alternative tried 3= i create a rigid element by holding on to the nodes which are all having the Uniform Distributed Load and define a load to the center node.....but i have a doubt that wen the nodes selected are in a irregular lamina then the main node is not formed in the center but offsetted some where else so at this point does the uniform distributed load is acting perfectly or else it causes some additional moments are forces on the spots in the far away spots..... and what should be the card image used
  10. thanks rahul and johnson for ur reply,.... i made it through washer split..... i have another ques on UNIFORM DISTIBUTED LOAD and i will create a topic...expecting ur reply in that too
  11. THE MODEL SHOWN IN RED NEEDS TO BE SPLIT UP TO DEFINE LOAD, THE OTHER CROSSSECTION MODEL SHOWN IN PINK IS THE COMPONENT IN CONTACT, SO I HAVE TO SPLIT MY RED COMPONENT ACCORDING TO THE INTERFACE COMPONENT i.e THE PINK COMPONENT TO ASSIGN LOADS ONLY IN THAT SPOT AND I WANT 6 SEGMENTS OF 10 MM THICKNESS.
  12. i got a problem of 1% Jacobian while meshing a 2d plane surface of a 3d object which was to be spinned. so to avoid jocobian i started splitting the elements and it has passed the jacobian but i have a doubt whether non-connected nodes may raise any problem during solution. but for the element quality check these elements have passed
  13. Hypermesh is Non-Dimensional but for our ease by default one can keep Force in N, Displacement in mm,Time in S and Mass in Tonne..... U can see that while assigning the materials the unit of density will be in tonne/mm3 by default i.e by default when we click for the density in the material collector it displays density of steel as 7.9e-9 which is conversion of density of steel 7900 kg/m3 to 7.9e-9 tonne/mm3 1 kilogram / cubic meter = 1.0 × 10-12 tonne / cubic millimeter...... And for your purpose keeping Moment in N*mm will be right if u follow the above unit system.
  14. hi prakash i have tried that RBE3 idea but it is stating that max num of independent nodes for a RBE3 i.e 10000 has been exceeded so am not able to create a RBE3 with respect to a node at center for the whole surface in a single go..... but i have partitioned the surface and gave two RBE3 elements .and have constrained same as like u have said me...........but will partitioning and giving two RBE3 With respect to a single node will affect my results......
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