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Dung the most handsome man

Calculate the sum of a series

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Hi Dung,

you can get more accurate result by having a tolerance condition inside a while loop. something like below:



clc, clear
sum = 0;
sum_before = realmax;
tol = 1e-12;  % tolerance value
i = 0;

while (abs(sum_before - sum) >= tol) 
    i= i+ 1;
    sum_before = sum;
    sum = sum + 1/(i^2);        


Hope this helps



Manoj kandukuri

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